the area enclosed by the curve y=4x - x^2 and the x axis is:

a) 10 2/3 b) 0 c) -10 2/3 d) 32

please can someone help??

y=4x-x^2 cuts the x-axis at y=0 then,x=0,x=4 so int.4x-x^2 from x=0 to x=4 then 2x^2-x^3/3=(2*4^2-4^3/3)-(0)=32/3:fight:

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the area enclosed by the curve y=4x - x^2 and the x axis is:

a) 10 2/3

b) 0

c) -10 2/3

d) 32

please can someone help??

y=4x-x^2 cuts the x-axis at y=0 then,x=0,x=4 so int.4x-x^2 from x=0 to x=4 then 2x^2-x^3/3=(2*4^2-4^3/3)-(0)=32/3:fight: